Math  /  Trigonometry

QuestionFind the value of tanπ8cot3π8secπ8csc3π8\tan \frac{\pi}{8} \cot \frac{3 \pi}{8} - \sec \frac{\pi}{8} \csc \frac{3 \pi}{8}.

Studdy Solution
Finally, we can simplify the above expression to get the exact value of the given expression.
22(cos(π8)sin(π8)cos(π8))22(cos(π8)+sin(π8))=22=0\frac{\sqrt{2}}{2}(\frac{\cos(\frac{\pi}{8}) - \sin(\frac{\pi}{8})}{\cos(\frac{\pi}{8})}) - \frac{2}{\sqrt{2}(\cos(\frac{\pi}{8}) + \sin(\frac{\pi}{8}))} = \sqrt{2} - \sqrt{2} =0So, the exact value of tanπ8cot3π8secπ8csc3π8\tan \frac{\pi}{8} \cot \frac{3 \pi}{8}-\sec \frac{\pi}{8} \csc \frac{3 \pi}{8} is0.

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