Math / AlgebraQuestionFind the inverse for each of the following functions. f(x)=15x+12f−1(x)=□g(x)=6x3−3g−1(x)=h(x)=15x+3h−1(x)=□j(x)=x+63j−1(x)=□\begin{array}{l} f(x)=15 x+12 \\ f^{-1}(x)=\square \\ g(x)=6 x^{3}-3 \\ g^{-1}(x)= \\ h(x)=\frac{15}{x+3} \\ h^{-1}(x)=\square \\ j(x)=\sqrt[3]{x+6} \\ j^{-1}(x)=\square \end{array}f(x)=15x+12f−1(x)=□g(x)=6x3−3g−1(x)=h(x)=x+315h−1(x)=□j(x)=3x+6j−1(x)=□ □\square□ □\square□ □\square□ □\square□Studdy SolutionThe inverse function is:j−1(x)=x3−6 j^{-1}(x) = x^3 - 6 j−1(x)=x3−6 The inverses of the functions are:f−1(x)=x−1215 f^{-1}(x) = \frac{x - 12}{15} f−1(x)=15x−12 g−1(x)=x+363 g^{-1}(x) = \sqrt[3]{\frac{x + 3}{6}} g−1(x)=36x+3 h−1(x)=15−3xx h^{-1}(x) = \frac{15 - 3x}{x} h−1(x)=x15−3x j−1(x)=x3−6 j^{-1}(x) = x^3 - 6 j−1(x)=x3−6View Full Solution - FreeWas this helpful?