Math  /  Calculus

QuestionFind the inverse Laplace transform of 2ss2+6s+1\frac{2s}{s^{2}+6s+1}.

Studdy Solution
Thus, the inverse Laplace transform of 2ss2+6s+1\frac{2s}{s^2 + 6s + 1} is:
f(t)=e3t(2cosh(8t)322sinh(8t))f(t) = e^{-3t} \left(2 \cosh(\sqrt{8}t) - \frac{3\sqrt{2}}{2} \sinh(\sqrt{8}t)\right)

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