Math  /  Algebra

QuestionFind the inverse of [112011102]\left[\begin{array}{ccc} 1 & -1 & 2 \\ 0 & -1 & -1 \\ 1 & 0 & 2 \end{array}\right]

Studdy Solution
Calculate the inverse using the formula:
A1=1det(A)adjugate(A)A^{-1} = \frac{1}{\text{det}(A)} \cdot \text{adjugate}(A)
Since det(A)=1\text{det}(A) = 1, the inverse is simply the adjugate:
A1=[221100111]A^{-1} = \begin{bmatrix} -2 & 2 & 1 \\ -1 & 0 & 0 \\ 1 & -1 & -1 \end{bmatrix}
The inverse of the given matrix is:
[221100111]\boxed{\begin{bmatrix} -2 & 2 & 1 \\ -1 & 0 & 0 \\ 1 & -1 & -1 \end{bmatrix}}

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