Math  /  Calculus

Questionlimx(2x23x25x+3)\lim _{x \rightarrow \infty}\left(\frac{2 x^{2}-3}{x^{2}-5 x+3}\right)

Studdy Solution
Evaluate the limit as xx approaches infinity:
As xx \rightarrow \infty, the terms 3x2\frac{3}{x^2}, 5x\frac{5}{x}, and 3x2\frac{3}{x^2} all approach 00.
Thus, the expression simplifies to:
2010+0=21=2\frac{2 - 0}{1 - 0 + 0} = \frac{2}{1} = 2
The value of the limit is:
2\boxed{2}

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