QuestionFind the limit $L$ (if it exists). (If an answer does not exist, enter DNE.) $$\begin{array}{l} \lim _{x \rightarrow 9^{-}} \frac{x-9}{x^{2}-81} \\ L=\square \end{array}$$
If it does not exist, explain why. The limit does not exist at $x=9$ because the function approaches different values from the left and right side of 9. The limit does not exist at $x=9$ because the function value is undefined at $x=9$. The limit does not exist at $x=9$ because the function does not approach $f(9)$ as $x$ approaches 9 . The limit does not exist at $x=9$ because the function is not continuous at any $x$ value. The limit exists at $x=9$.