Math / Calculus

QuestionSubmit Answer 11. [-/1 Points] DETAILS MY NOTES SCALCET9M 4.4.015.
Find the limit. Use l'Hospital's Rule where appropriate. If there is a more elementary method, consider using it. $\lim _{t \rightarrow 0} \frac{e^{8 t}-1}{\sin (t)}$ $\square$ Need Help? Read It Watch It Submit Answer
12. [-/1 Points] DETAILS

Studdy Solution
Evaluate the limit by substituting $t = 0$ in the expression obtained after applying l'Hospital's Rule.
$\lim_{t \to 0} \frac{8e^{8t}}{\cos(t)} = \frac{8e^{8 \cdot 0}}{\cos(0)} = \frac{8 \cdot 1}{1} = 8$
The limit is 8.

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