Math  /  Calculus

QuestionFind the Maclaurin series for f(x)f(x) using the definition of a Maclaurin series. [Assume that ff has a power series expansion. Do not show that Rn(x)0R_{n}(x) \rightarrow 0.] f(x)=3xf(x)=n=0()\begin{array}{c} f(x)=3^{x} \\ f(x)=\sum_{n=0}^{\infty}(\square) \end{array}
Find the associated radius of convergence RR. R=R= \square

Studdy Solution
The Maclaurin series for f(x)=3xf(x) = 3^x is n=0(ln3)nn!xn.\sum_{n=0}^{\infty} \frac{(\ln 3)^n}{n!} x^n. The radius of convergence is R=R = \infty.

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