QuestionFind the missing coordinate $y$ for the point $\left(-\frac{1}{4}, y\right)$ on the unit circle in quadrant III.

Studdy Solution
implify the square root. The square root of16 in the denominator is4.
$$y = -\frac{\sqrt{15}}{4}$$So, the missing coordinate of the point $\left(-\frac{1}{4}, y\right)$ that lies on the graph of the unit circle in quadrant III is $y = -\frac{\sqrt{15}}{4}$.