Question Find the value of $c$ that satisfies the Mean Value Theorem for $h(x) = \sqrt{3x-3}$ on the interval $4 \leq x \leq 13$.

Studdy Solution
Simplify the fraction to find the final value of $c$.
$$c = \frac{93}{12} = \frac{31}{4} = 7.75$$
The number $c$ that satisfies the Mean Value Theorem for $h$ on the interval $4 \leq x \leq 13$ is $c = 7.75$.