QuestionFind the partial fraction decomposition of the given rational expression. $$\frac{6}{x(x-3)}$$

Studdy Solution
Substitute the values of $A$ and $B$ back into the partial fractions:
$\frac{6}{x(x-3)} = \frac{-2}{x} + \frac{2}{x-3}$
The partial fraction decomposition is:
$\frac{6}{x(x-3)} = \frac{-2}{x} + \frac{2}{x-3}$