Math  /  Trigonometry

QuestionFind the polar coordinates, 0θ<2π0 \leq \theta<2 \pi and r0r \geq 0, of the point given in Cartesian coordinates. A) (2,5π4)\left(2, \frac{5 \pi}{4}\right) B) (2,7π4)\left(2, \frac{7 \pi}{4}\right) (2,2)(\sqrt{2},-\sqrt{2}) C) (2,7π4)\left(\sqrt{2}, \frac{7 \pi}{4}\right) D) (4,5π4)\left(4, \frac{5 \pi}{4}\right)

Studdy Solution
Match the calculated polar coordinates (r,θ)=(2,7π4)(r, \theta) = (2, \frac{7\pi}{4}) with the given options:
A) (2,5π4)(2, \frac{5\pi}{4}) B) (2,7π4)(2, \frac{7\pi}{4}) C) (2,7π4)(\sqrt{2}, \frac{7\pi}{4}) D) (4,5π4)(4, \frac{5\pi}{4})
The correct match is option B: (2,7π4)(2, \frac{7\pi}{4}).
The polar coordinates of the point (2,2)(\sqrt{2}, -\sqrt{2}) are:
(2,7π4) \boxed{(2, \frac{7\pi}{4})}

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