Math  /  Algebra

QuestionFind the product: (x2y)(3x22xy)2y2(x-2y)(3x^{2}-2xy)2y^{2}.

Studdy Solution
Now, multiply the result from the previous step by 2y22y^{2}2y2(3x38x2y+4xy2)=x3y216x2y3+8xy42y^{2}(3x^{3} -8x^{2}y +4xy^{2}) =x^{3}y^{2} -16x^{2}y^{3} +8xy^{4}The product of the given expression is x3y216x2y3+8xy4x^{3}y^{2} -16x^{2}y^{3} +8xy^{4}.

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