QuestionFind the slant asymptote of the function. $$f(x)=\frac{12 x^{3}+4 x^{2}-9 x-8}{4 x^{2}-3}$$
The slant asymptote is at $y=$ $\square$

Studdy Solution
The quotient from the division is $3x + 1$, which represents the slant asymptote.
Thus, the slant asymptote is at $y = 3x + 1$.
The slant asymptote is at $y = \boxed{3x + 1}$.