Math  /  Algebra

QuestionFind the solution of the exponential equation e2x+1=24e^{2 x+1}=24 in terms of logarithms, or correct to four decimal places. x=x=

Studdy Solution
The solution to the equation e2x+1=24e^{2x+1} = 24 is x=ln(24)12x = \frac{\ln(24) - 1}{2}, which is approximately 1.08901.0890.

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