Math  /  Measurement

Question Find the solution of the equation y2y1+2y3y1=1\frac{y^{2}}{y-1}+\frac{2y-3}{y-1}=1.

Studdy Solution
The solution to the equation is the remaining value of yy.
y=2y = -2
The correct answer is d. {2}\{-2\}.

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