Math  /  Geometry

QuestionFind the value of aa, if the distance between the points A(3,14)A(-3,-14) and B(a,5)B(a,-5) is 9 units.

Studdy Solution
Solve for a a :
Square both sides to eliminate the square root:
92=(a+3)2+92 9^2 = (a + 3)^2 + 9^2
81=(a+3)2+81 81 = (a + 3)^2 + 81
Subtract 81 from both sides:
0=(a+3)2 0 = (a + 3)^2
Take the square root of both sides:
a+3=0 a + 3 = 0
Solve for a a :
a=3 a = -3
The value of a a is:
3 \boxed{-3}

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