QuestionFind $c$ for the function defined by $f(x) = x^2 - 4$ if $x \leq c$ and $f(x) = 6x - 13$ if $x > c$ to ensure continuity. $$c =$$

Studdy Solution
Since the square root of a negative number is not a real number, there are no real solutions for $c$. Therefore, the function $f(x)$ cannot be continuous everywhere for any real value of $c$.
The solution is that there is no real value of $c$ for which the function $f(x)$ is continuous everywhere.