Question Find the value of $t$ that satisfies the equation $V(t)=4t^3-27t^2$.

Studdy Solution
olving the second equation $4t -27 =0$ gives us the second solution.
$$4t =27$$$$t = \frac{27}{4} =6.75$$So, the values of $t$ for which $V(t)=0$ are $t=0$ and $t=6.75$.