Math  /  Measurement

Question Find the value of xx in the simplified expression gx+h3=1g6+1h3g^{x} + h^{-3} = \frac{1}{g^{6}} + \frac{1}{h^{3}}.

Studdy Solution
Now that we have gx=g6g^{x} = g^{-6}, we can equate the exponents since the bases are the same and non-zero.
x=6x = -6
The value of xx is 6-6.

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