Math  /  Calculus

QuestionFind yy^{\prime}. y=(2x3)3(x2+5)4y=\sqrt{(2 x-3)^{3}\left(x^{2}+5\right)^{4}} ++
Choose the correct answer below. A. y=(x2+5)(11x212x+15)2x3y^{\prime}=\frac{\left(x^{2}+5\right)\left(11 x^{2}-12 x+15\right)}{\sqrt{2 x-3}} B. y=2x3(x2+5)(11x212x+15)y^{\prime}=\sqrt{2 x-3}\left(x^{2}+5\right)\left(11 x^{2}-12 x+15\right) C. y=x2+5(2x3)(10x2+6x30)y^{\prime}=\sqrt{x^{2}+5}(2 x-3)\left(10 x^{2}+6 x-30\right) D. y=(2x3)(10x2+6x30)x2+5y^{\prime}=\frac{(2 x-3)\left(10 x^{2}+6 x-30\right)}{\sqrt{x^{2}+5}}

Studdy Solution
y=2x3(x2+5)(11x212x+15)y^{\prime} = \sqrt{2x-3}(x^2+5)(11x^2-12x+15).
Doğru cevap B seçeneğidir.

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