Math  /  Data & Statistics

QuestionFor a binomial experiment with a n=9\mathrm{n}=9 trials, each with a success probability p=0.79\mathrm{p}=0.79, what is the probability of obtaining less than 5 successes?
Your answer: 0.404 0.147 0.081 0.024 0.107 0.545 0.976 0.541 0.878 0.189

Studdy Solution
Sum the calculated probabilities to find the total probability of obtaining less than 5 successes.
The calculated probabilities are approximately:
P(X=0)0.000006 P(X = 0) \approx 0.000006 P(X=1)0.000204 P(X = 1) \approx 0.000204 P(X=2)0.002328 P(X = 2) \approx 0.002328 P(X=3)0.016308 P(X = 3) \approx 0.016308 P(X=4)0.069912 P(X = 4) \approx 0.069912
Summing these gives:
P(X<5)0.000006+0.000204+0.002328+0.016308+0.069912=0.088758 P(X < 5) \approx 0.000006 + 0.000204 + 0.002328 + 0.016308 + 0.069912 = 0.088758
The probability of obtaining less than 5 successes is approximately:
0.088758 \boxed{0.088758}

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