QuestionIdentify which equation does not define a trigonometric function for a point $P(x, y)$ on the unit circle: A. $\cot t=\frac{y}{x}, x \neq 0$ B. $\csc t=\frac{1}{y}, y \neq 0$ C. $\cos t=x$ D. $\sec t=\frac{1}{x}, x \neq 0$

Studdy Solution
Finally, let's consider option D.
Option D $\sec t = \frac{1}{x}$, $x \neq0$
This is not the correct definition of the secant function. The secant function is defined as the reciprocal of the cosine function, and in terms of $x$ and $y$ coordinates on the unit circle, it should be $\sec t = \frac{1}{\cos t} = \frac{1}{x}$, where $x$ is not equal to zero.
Therefore, the equation that does not accurately define a trigonometric function is option D $\sec t = \frac{1}{x}$, $x \neq0$.