Math  /  Algebra

QuestionFor each scenario below, find the matching growth or decay model, f(t)f(t). $100\$ 100 million dollars is invested in a compound interest account. The interest rate is 5\%, compounded every half a year. \qquad The concentration of pollutants in a lake is initially 100 ppm. The concentration decays by 30%30 \% every 3 years. The concentration of pollutants in a lake is initially 100 ppm. The concentration decays by 70\% every 3 years. 100 bacteria begin a colony in a petri dish. The bacteria increase by 30%30 \% every 3 hours. 100 bacteria begin a colony in a petri dish. The bacteria increase by 200\% every half hour. \square The cost of producing high end shoes is currently $100\$ 100. The cost is increasing by 50%50 \% every two years.
1. f(t)=100(0.7t3)f(t)=100\left(0.7^{\frac{t}{3}}\right)
2. f(t)=100(0.3t3)f(t)=100\left(0.3^{\frac{t}{3}}\right)
3. f(t)=100(1.3t3)f(t)=100\left(1.3^{\frac{t}{3}}\right)
4. f(t)=100(32t)f(t)=100\left(3^{2 t}\right)
5. f(t)=100(1.5t2)f(t)=100\left(1.5^{\frac{t}{2}}\right)
6. f(t)=100(1.052t)f(t)=100\left(1.05^{2 t}\right)

Studdy Solution
1. f(t)=100(1.052t)f(t)=100(1.05^{2t})
2. f(t)=100(0.7t3)f(t)=100(0.7^{\frac{t}{3}})
3. f(t)=100(0.3t3)f(t)=100(0.3^{\frac{t}{3}})
4. f(t)=100(1.3t3)f(t)=100(1.3^{\frac{t}{3}})
5. f(t)=100(32t)f(t)=100(3^{2t})
6. f(t)=100(1.5t2)f(t)=100(1.5^{\frac{t}{2}})

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