Math  /  Algebra

QuestionFind the range of the function y=3x+42y=3 \sqrt{x+4}-2.

Studdy Solution
Since the graph opens upwards and the minimum value is -2, the range of the function is all y-values greater than or equal to -2.
The range of the function y=3x+42y=3 \sqrt{x+4}-2 is y2y \geq -2.

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