Math  /  Algebra

QuestionFor the given function, find the indicated function values. Find the domain of the function. f(x)=2x+18f(x)=\sqrt{2 x+18}, find f(0),f(1),f(4),f(8)f(0), f(1), f(4), f(-8).

Studdy Solution
Evaluate the function at x=8 x = -8 :
f(8)=2(8)+18 f(-8) = \sqrt{2(-8) + 18} f(8)=16+18 f(-8) = \sqrt{-16 + 18} f(8)=2 f(-8) = \sqrt{2}
The domain of the function is x9 x \geq -9 . The evaluated function values are: f(0)=32 f(0) = 3\sqrt{2} f(1)=25 f(1) = 2\sqrt{5} f(4)=26 f(4) = \sqrt{26} f(8)=2 f(-8) = \sqrt{2}

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