Math  /  Algebra

QuestionFor the polynomial below, 1 is a zero. h(x)=x3+3x22x2h(x)=x^{3}+3 x^{2}-2 x-2
Express h(x)h(x) as a product of linear factors. h(x)=h(x)=

Studdy Solution
We found all the factors!
The **final factored form** of h(x)h(x) is: h(x)=(x1)(x+22)(x+2+2) h(x) = (x-1)(x + 2 - \sqrt{2})(x + 2 + \sqrt{2})

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