MathQuestionFrom the following data, H2+Cl2→2HClΔH∘=−200 kJ2H2+O2→2H2OΔH∘=−500 kJ\begin{array}{c} \mathrm{H}_{2}+\mathrm{Cl}_{2} \rightarrow 2 \mathrm{HCl} \Delta \mathrm{H}^{\circ}=-200 \mathrm{~kJ} \\ 2 \mathrm{H}_{2}+\mathrm{O}_{2} \rightarrow 2 \mathrm{H}_{2} \mathrm{O} \Delta \mathrm{H}^{\circ}=-500 \mathrm{~kJ} \end{array}H2+Cl2→2HClΔH∘=−200 kJ2H2+O2→2H2OΔH∘=−500 kJ calculate ΔH∘(\Delta H^{\circ}(ΔH∘( in kJ))) for the following reaction: 4HCl+O2→2Cl2+2H2OΔH∘=? kJ4 \mathrm{HCl}+\mathrm{O}_{2} \rightarrow 2 \mathrm{Cl}_{2}+2 \mathrm{H}_{2} \mathrm{O} \Delta \mathrm{H}^{\circ}=? \mathrm{~kJ}4HCl+O2→2Cl2+2H2OΔH∘=? kJStuddy SolutionThe ΔH∘\Delta H^\circΔH∘ for the reaction 4HCl+O2→2Cl2+2H2O4\mathrm{HCl} + \mathrm{O}_2 \rightarrow 2\mathrm{Cl}_2 + 2\mathrm{H}_2\mathrm{O}4HCl+O2→2Cl2+2H2O is −100 kJ-100 \mathrm{~kJ}−100 kJ.View Full Solution - FreeWas this helpful?
