QuestionFind the derivative $f^{\prime}(x)$ of $f(x)=x^{3}+4 \sqrt{x}+\frac{1}{x}+2$ and the tangent line at $x=1$.

Studdy Solution
implify the equation to get the equation of the tangent line.
$$y =4x +4$$So, the derivative of the function $f(x)$ is $f^{\prime}(x) =3x^{2} + \frac{2}{\sqrt{x}} - \frac{}{x^{2}}$ and the equation of the tangent line to the curve $f(x)$ at $x=$ is $y =4x +4$.