Math  /  Algebra

QuestionFind (km)(x)(k \circ m)(x) and (mk)(x)(m \circ k)(x) for k(x)=9x5k(x)=9x-5 and m(x)=x2m(x)=x^2. Are they equal?

Studdy Solution
Finally, we compare (km)(x)(k \circ m)(x) and (mk)(x)(m \circ k)(x) to see if they are equal.
9x2581x290x+259x^{2} -5 \neq81x^{2} -90x +25 So, (km)(x)(mk)(x)(k \circ m)(x) \neq (m \circ k)(x).
The solutions are(a) (km)(x)=9x25(k \circ m)(x) =9x^{2} -5 (b) (mk)(x)=81x290x+25(m \circ k)(x) =81x^{2} -90x +25 (c) (km)(x)(mk)(x)(k \circ m)(x) \neq (m \circ k)(x)

View Full Solution - Free
Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord