QuestionGiven the following functions, find each of the values: $$\begin{array}{l} f(x)=x^{2}+6 x-7 \\ g(x)=x-1 \\ (f+g)(-3)= \\ (f-g)(1)= \\ (f \cdot g)(0)= \\ \left(\frac{f}{g}\right)(4)= \end{array}$$

Studdy Solution
Simplify the expression:
$$\left(\frac{f}{g}\right)(4) = \frac{16 + 24 - 7}{3}$$ $$= \frac{33}{3}$$ $$= 11$$
The values are:
$$(f+g)(-3) = -20$$ $$(f-g)(1) = 0$$ $$(f \cdot g)(0) = 7$$ $$\left(\frac{f}{g}\right)(4) = 11$$