QuestionFind $k$ in the function $g(x)=-3\left[\frac{1}{2(x-3)}\right]+1$ given $a=-3$, $d=3$, $c=1$.

Studdy Solution
So, the value of $k$ is $\frac{1}{2}$.
The values of $a$, $k$, $d$, and $c$ are $a=-3$, $k=\frac{1}{2}$, $d=3$, and $c=1$.