QuestionCalculate the mass change (in kg) per mole of $\mathrm{H}_{2}$ formed in the reaction: $\mathrm{H} + \mathrm{H} \rightarrow \mathrm{H}_{2}$, $\Delta H^{\circ}=-436.4 \mathrm{~kJ/mol}$.

Studdy Solution
Finally, we need to convert the change in mass from kg/mol to g/mol. We can do this by multiplying the calculated value by1000, because1 kg =1000 g.
$$\Delta m = -4.84 \times10^{-12} \, \mathrm{kg/mol} \times1000 = -4.84 \times10^{-9} \, \mathrm{g/mol}$$The change in mass per mole of $\mathrm{H}_{2}$ formed is $-4.84 \times10^{-9} \, \mathrm{g/mol}$.