QuestionGraph all vertical and horizontal asymptotes of the rational function. $$f(x)=\frac{x+1}{-x^{2}-6}$$

Studdy Solution
Determine the horizontal asymptote by comparing the degrees of the numerator and the denominator:
- The degree of the numerator $x + 1$ is 1. - The degree of the denominator $-x^2 - 6$ is 2.
Since the degree of the numerator is less than the degree of the denominator, the horizontal asymptote is $y = 0$.
The graph of the function $f(x) = \frac{x+1}{-x^2-6}$ has a horizontal asymptote at $y = 0$ and no vertical asymptotes.