Math  /  Algebra

QuestionHence, or otherwise, solve the following equation, where xRx \in \mathbb{R} : 24x+1=1282^{4 x+1}=128

Studdy Solution
Solve for x x by first subtracting 1 from both sides:
4x+1=7 4x + 1 = 7 4x=71 4x = 7 - 1 4x=6 4x = 6
Then, divide both sides by 4:
x=64 x = \frac{6}{4} x=32 x = \frac{3}{2}
The value of x x is:
32 \boxed{\frac{3}{2}}

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