Math  /  Data & Statistics

QuestionHere are summary statistics for the weights of Pepsi in randomly selected cans: n=36n=36, xˉ=0.82408lb,s=0.00568lb\bar{x}=0.82408 \mathrm{lb}, \mathrm{s}=0.00568 \mathrm{lb}. Use a confidence level of 99%99 \% to complete parts (a) through (d) below. a. Identify the critical value tα/2t_{\alpha / 2} used for finding the margin of error. tα/2=2.72t_{\alpha / 2}=2.72 (Round to two decimal places as needed.) b. Find the margin of error. E=0.00257lbE=0.00257 \mathrm{lb} (Round to five decimal places as needed.) c. Find the confidence interval estimate of μ\mu. \square lb<μ<\mathrm{lb}<\mu< \square lb (Round to five decimal places as needed.)

Studdy Solution
Calculate the confidence interval:
0.82151<μ<0.82665 0.82151 < \mu < 0.82665
The confidence interval estimate for μ\mu is:
0.82151lb<μ<0.82665lb \boxed{0.82151 \, \text{lb} < \mu < 0.82665 \, \text{lb}}

View Full Solution - Free
Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord