QuestionHow many atoms are in a $6.21 \mu \mathrm{mol}$ helium sample? Answer with correct sig figs using ${ }^{*} 10^{\wedge}$.

Studdy Solution
Calculate the number of atoms.
$$Number\, of\, atoms =6.21 \times10^{-6} \times6.02214076 \times10^{23} =3.74 \times10^{18} \mathrm{atoms}$$The number of atoms in a $6.21 \mu \mathrm{mol}$ sample of pure helium is $3.74 \times10^{18}$ atoms.