QuestionHow many mL of a $2\% \mathrm{w}/\mathrm{v}$ ammonium chloride solution is needed for $75 \mathrm{mEq}$?

Studdy Solution
Calculate the volume in ml.
$$x = \frac{401.5\, mg \\times100\, ml}{2000\, mg} =200.625\, ml$$The patient should be administered approximately200.625 ml of the% w/v solution of NH4Cl.