Math  /  Algebra

Questionh(x)={5x17, for x<31, for 3x<1x+4, for x1h(10)=h(2)=h(1)=h(4)=\begin{array}{l}h(x)=\left\{\begin{array}{ll}-5 x-17, & \text { for } x<-3 \\ 1, & \text { for }-3 \leq x<1 \\ x+4, & \text { for } x \geq 1\end{array}\right. \\ h(-10)=\square \\ h(-2)=\square \\ h(1)=\square \\ h(4)=\square\end{array}

Studdy Solution
Evaluate the function at x=4 x = 4 :
Since x=4 x = 4 and x1 x \geq 1 , we use h(x)=x+4 h(x) = x + 4 .
h(4)=4+4 h(4) = 4 + 4 h(4)=8 h(4) = 8
The evaluated values are: h(10)=33 h(-10) = 33 h(2)=1 h(-2) = 1 h(1)=5 h(1) = 5 h(4)=8 h(4) = 8

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