Math  /  Geometry

Question(I) A jet plane traveling 1890 km/h(525 m/s)1890 \mathrm{~km} / \mathrm{h}(525 \mathrm{~m} / \mathrm{s}) pulls out of a dive by moving in an arc of radius 4.80 km . What is the plane's acceleration in gg 's?

Studdy Solution
Convert the acceleration to g g 's by dividing by g=9.81m/s2 g = 9.81 \, \text{m/s}^2 :
ac=57.42m/s29.81m/s2 a_c = \frac{57.42 \, \text{m/s}^2}{9.81 \, \text{m/s}^2} ac5.85g a_c \approx 5.85 \, g
The plane's acceleration is approximately:
5.85g \boxed{5.85 \, g}

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