Math / Geometry

QuestionFind the density of $80 \mathrm{~g}$ of lead with dimensions $2 \mathrm{~cm} \times 3 \mathrm{~cm} \times 5 \mathrm{~cm}$ . Options: a. $2.67 \mathrm{~g} / \mathrm{cm}^{3}$ b. $0.38 \mathrm{~g} / \mathrm{cm}^{3}$ c. $30 \mathrm{~g} / \mathrm{cm}^{3}$ d. $2,400 \mathrm{~g} / \mathrm{cm}^{3}$

Studdy Solution
Calculate the density of the lead.
$Density =80\,g /30\,cm^{3} =2.67\,g/cm^{3}$ The density of the lead is $2.67 \mathrm{~g} / \mathrm{cm}^{3}$ .

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