Math  /  Trigonometry

QuestionIf θ=240\theta=240^{\circ}, find the exact value of each expression below. (a) 2cosθ=2 \cos \theta= \square (b) cosθ2=\quad \cos \frac{\theta}{2}= \square (c) cos2θ=\cos ^{2} \theta= \square

Studdy Solution
Calculate cos2θ\cos^2 \theta:
cos2240=(cos240)2 \cos^2 240^\circ = \left(\cos 240^\circ\right)^2
=(12)2 = \left(-\frac{1}{2}\right)^2
=14 = \frac{1}{4}
The exact values are: (a) 2cosθ=12 \cos \theta = -1 (b) cosθ2=12\cos \frac{\theta}{2} = -\frac{1}{2} (c) cos2θ=14\cos^2 \theta = \frac{1}{4}

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