QuestionA basketball player shoots from 6 ft high at 45 degrees. Use $h(x)=-\frac{44 x^{2}}{25^{2}}+x+6$ to find height at $x=3$.

Studdy Solution
Calculate the final value of $h(3)$.
$$h(3)=-0.6344+9=.3656$$The height of the ball after it has traveled3 feet in front of the foul line is approximately.37 feet (rounded to two decimal places).