QuestionIf a cup of coffee has temperature $91^{\circ} \mathrm{C}$ in a room where the ambient air temperature is $19^{\circ} \mathrm{C}$, then, according to Newton's Law of Cooling, the temperature of the coffee after $t$ minutes is $T(t)=19+72 e^{-t / 48}$. What is the average temperature of the coffee during the first 16 minutes? average temp = $\square$ 91 ${ }^{\circ} \mathrm{C}$