Math  /  Algebra

QuestionIf we graph of a ioganthernic function is given. Seslect the function for the graph from the oppliogrim A. f(x)=log4(x2)f(x)=\log _{4}(x-2) B. f(x)=log4xf(x)=\log _{4} x C. f(x)=log4(x+2)f(x)=\log _{4}(x+2) D. f(x)=log4x+2f(x)=\log _{4} x+2

Studdy Solution
Conclude that the correct function is f(x)=log4(x2) f(x) = \log_{4}(x - 2) .
The function with a vertical asymptote at x=2 x = 2 and passing through (3,0) (3, 0) is:
f(x)=log4(x2) \boxed{f(x) = \log_{4}(x - 2)}

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