Math  /  Calculus

QuestionShow that if y=5+xxy=\frac{5+\sqrt{x}}{\sqrt{x}}, then 6dydx+4xd2ydx2=06 \frac{d y}{d x}+4 x \frac{d^{2} y}{d x^{2}}=0.

Studdy Solution
The equation simplifies to0, which is what we needed to prove.
=0=0We have shown that 6dydx+4xd2ydx2=06 \frac{d y}{d x}+4 x \frac{d^{2} y}{d x^{2}}=0.

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