Math  /  Algebra

Question(II) A 1200N1200-\mathrm{N} crate rests on the floor. How much work is required to move it at constant speed (a) 6.0 m along the floor against a friction force of 230 N , and (b) 6.0 m vertically?

Studdy Solution
Calculate the work done moving the crate vertically.
The work done to lift the crate vertically is given by the formula: W=F×d W = F \times d where F F is the weight of the crate and d d is the vertical distance.
Substitute the given values: W=1200N×6.0m W = 1200 \, \text{N} \times 6.0 \, \text{m}
Calculate: W=7200J W = 7200 \, \text{J}
The work required to move the crate (a) along the floor is 1380J 1380 \, \text{J} and (b) vertically is 7200J 7200 \, \text{J} .

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