Math  /  Algebra

Question(II) A box of mass 4.0 kg is accelerated from rest by a force across a floor at a rate of 2.0 m/s22.0 \mathrm{~m} / \mathrm{s}^{2} for 8.0 s . Find the net work done on the box.

Studdy Solution
Calculate the net work done using the work-energy principle:
Wnet=ΔKE=12mv212mu2 W_{\text{net}} = \Delta KE = \frac{1}{2}mv^2 - \frac{1}{2}mu^2
where m=4.0kg m = 4.0 \, \text{kg} , v=16.0m/s v = 16.0 \, \text{m/s} , and u=0m/s u = 0 \, \text{m/s} .
Wnet=12(4.0kg)(16.0m/s)212(4.0kg)(0)2 W_{\text{net}} = \frac{1}{2}(4.0 \, \text{kg})(16.0 \, \text{m/s})^2 - \frac{1}{2}(4.0 \, \text{kg})(0)^2 Wnet=12(4.0)(256.0) W_{\text{net}} = \frac{1}{2}(4.0)(256.0) Wnet=512.0J W_{\text{net}} = 512.0 \, \text{J}
The net work done on the box is:
512.0J \boxed{512.0 \, \text{J}}

View Full Solution - Free
Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord