Math  /  Word Problems

QuestionCalculate the terminal voltage (in p.u.) of a synchronous machine with a load of 50MW50 \mathrm{MW} at 0.8pf0.8 \mathrm{pf} lagging, given transformer reactances of 0.10p.u.0.10 \mathrm{p.u.} and 0.12p.u.0.12 \mathrm{p.u.}, and a line impedance of j100Ωj100 \, \Omega. Confirm the sub-transient reactance and impedance units.

Studdy Solution
Calculate the terminal voltage of the synchronous machine.
Vterminal=1.625×(.22+j9.18)=.8625j5.7375p.u.V_{terminal} =1 -.625 \times (.22 + j9.18) =.8625 - j5.7375 \, \mathrm{p.u.}The terminal voltage of the synchronous machine is .8625j5.7375p.u..8625 - j5.7375 \, \mathrm{p.u.}.

View Full Solution - Free
Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord