Math  /  Calculus

QuestionIn Problems 1-32, use a table or a graph to investigate each limit.
1. limx2(x24x+1)\lim _{x \rightarrow 2}\left(x^{2}-4 x+1\right)
2. limx2x2+3x+2\lim _{x \rightarrow 2} \frac{x^{2}+3}{x+2}
3. limx12x1+x2\lim _{x \rightarrow-1} \frac{2 x}{1+x^{2}}
4. lims2s(s24)\lim _{s \rightarrow 2} s\left(s^{2}-4\right)
5. limxπ3cosx4\lim _{x \rightarrow \pi} 3 \cos \frac{x}{4}
6. limtπ/9sin(3t)\lim _{t \rightarrow \pi / 9} \sin (3 t)
7. limxπ/22secx3\lim _{x \rightarrow \pi / 2} 2 \sec \frac{x}{3}
8. limxπ/2tanxπ/22\lim _{x \rightarrow \pi / 2} \tan \frac{x-\pi / 2}{2}
9. limx2ex2/2\lim _{x \rightarrow-2} e^{-x^{2} / 2}
10. limx0ex+12x+3\lim _{x \rightarrow 0} \frac{e^{x}+1}{2 x+3}
11. limx0ln(x+1)\lim _{x \rightarrow 0} \ln (x+1)
12. limtelnt3\lim _{t \rightarrow e} \ln t^{3}
13. limx3x216x4\lim _{x \rightarrow 3} \frac{x^{2}-16}{x-4}
14. limx2x24x+2\lim _{x \rightarrow 2} \frac{x^{2}-4}{x+2}
15. limxπ/2sin(2x)\lim _{x \rightarrow \pi / 2} \sin (2 x)
16. limxπ/2cos(xπ)\lim _{x \rightarrow \pi / 2} \cos (x-\pi)
17. limx011+x2\lim _{x \rightarrow 0} \frac{1}{1+x^{2}}
18. limx01x21\lim _{x \rightarrow 0} \frac{1}{x^{2}-1}
19. limx0+(1ex)\lim _{x \rightarrow 0^{+}}\left(1-e^{-x}\right)
20. limx0(1+ex)\lim _{x \rightarrow 0^{-}}\left(1+e^{x}\right)
21. limx42x4\lim _{x \rightarrow 4^{-}} \frac{2}{x-4}
22. limx3+1x3\lim _{x \rightarrow 3^{+}} \frac{1}{x-3}
23. limx121x\lim _{x \rightarrow 1^{-}} \frac{2}{1-x}
24. limx2+42x\lim _{x \rightarrow 2^{+}} \frac{4}{2-x}
25. limx111x2\lim _{x \rightarrow 1^{-}} \frac{1}{1-x^{2}}
26. limx2+2x24\lim _{x \rightarrow 2^{+}} \frac{2}{x^{2}-4}
27. limx31(x3)2\lim _{x \rightarrow 3} \frac{1}{(x-3)^{2}}
28. limx01x2x2\lim _{x \rightarrow 0} \frac{1-x^{2}}{x^{2}}
29. limx0x2+93x2\lim _{x \rightarrow 0} \frac{\sqrt{x^{2}+9}-3}{x^{2}}
30. limx0x2+42x\lim _{x \rightarrow 0} \frac{\sqrt{x^{2}+4}-2}{x}
31. limx011x2x2\lim _{x \rightarrow 0} \frac{1-\sqrt{1-x^{2}}}{x^{2}}
32. limx02x22x\lim _{x \rightarrow 0} \frac{\sqrt{2-x}-\sqrt{2}}{2 x}

Studdy Solution
Confirm the limit using algebraic manipulation if necessary. For limx2(x24x+1)\lim_{x \rightarrow 2}(x^2 - 4x + 1), substitute x=2 x = 2 directly into the function: f(2)=224(2)+1=48+1=3 f(2) = 2^2 - 4(2) + 1 = 4 - 8 + 1 = -3
The limit is 3\boxed{-3}.
Repeat similar steps for each of the other limits, adjusting the values and functions as necessary.

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